Recipe 1.6 Obtaining the Most- or Least-Significant Bits of a Number
Problem
You have a 32-bit integer value that
contains information in both its lower and upper 16 bits. You need a
method to get the 16 most-significant bits and/or the 16
least-significant bits of this value.
Solution
To get the most-significant bits (MSB) of an integer value, perform a
bitwise and between it and the value shown in the
following method:
public static int GetMSB(int intValue)
{
return (intValue & 0xFFFF0000);
}
To get the least-significant bits (LSB) of a value, use the following
method:
public static int GetLSB(int intValue)
{
return (intValue & 0x0000FFFF);
}
This technique can easily be modified to work with other sizes of
integers (e.g., 8-bit, 16-bit, or 64-bit); this trick is shown in the
Discussion section.
Discussion
In order to determine the values of the MSB of a number, use the
following bitwise AND operation:
uint intValue = Int32.MaxValue;
uint MSB = intValue & 0xFFFF0000;
// MSB == 0xFFFF0000
This method simply ANDs the number to another
number with all of the MSB set to 1. This method
will zero out all of the LSB, leaving the MSB intact.
In order to determine the values of the LSB of a number, use the
following bitwise AND operation:
uint intValue = Int32.MaxValue;
uint LSB = intValue & 0x0000FFFF;
// LSB == 0x0000FFFF
This method simply ANDs the number to another
number with all of the LSB set to 1, which zeroes
out all of the MSB, leaving the LSB intact.
The methods presented here accept only 32-bit integer values. To
allow this method to accept other numeric data types, you can simply
overload this method to accept any other data types that you require.
For example, if you need to also acquire the least-significant byte
or most-significant byte of a 16-bit integer, you could modify the
GetMSB method as follows:
public static int GetMSB(short shortValue)
{
return (shortValue & 0xFF00);
}
The GetLSB method is modified as shown here:
public static int GetLSB(short shortValue)
{
return (shortValue & 0x00FF);
}
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