Recipe 16.8 Switching Unknown Pointer Types
Problem
You need a generic
method that accepts two pointers and switches the addresses that each
pointer points to. In other words, if X points to
an integer variable Foo and Y
points to an integer variable Bar, you want to
switch X so that it points to
Bar and switch Y so that it
points to Foo.
Solution
Create
a method that accepts two void pointers. The
following method accepts two pointers to void by
reference. The by
reference is required since we are actually switching the
values contained in the pointer variables, not the value that the
pointer is pointing to:
public unsafe void Switch(ref void* x, ref void* y)
{
void* temp = x;
x = y;
y = temp;
}
The following test code calls the Switch method
with two integer variables that point to different memory locations:
public unsafe void TestSwitch( )
{
int x = 100;
int y = 20;
int* ptrx = &x;
int* ptry = &y;
Console.WriteLine(*ptrx + "\t" + (int)ptrx);
Console.WriteLine(*ptry + "\t" + (int)ptry);
// Convert int* to void*
void* voidx = (void*)ptrx;
void* voidy = (void*)ptry;
// Switch pointer values
Switch(ref voidx, ref voidy);
// Convert returned void* to a usable int*
ptrx = (int*)voidx;
ptry = (int*)voidy;
Console.WriteLine(*ptrx + "\t" + (int)ptrx);
Console.WriteLine(*ptry + "\t" + (int)ptry);
}
The following is displayed:
100 1243108
20 1243104
20 1243104
100 1243108
The TestSwitch method could just have easily been
written with another data type, such as a byte,
shown here:
public unsafe void TestSwitch( )
{
byte x = 100;
byte y = 20;
byte* ptrx = &x;
byte* ptry = &y;
Console.WriteLine(*ptrx + "\t" + (int)ptrx);
Console.WriteLine(*ptry + "\t" + (int)ptry);
// Convert byte* to void*
void* voidx = (void*)ptrx;
void* voidy = (void*)ptry;
// Switch pointer values
Switch(ref voidx, ref voidy);
// Convert returned void* to a usable byte*
ptrx = (byte*)voidx;
ptry = (byte*)voidy;
Console.WriteLine(*ptrx + "\t" + (int)ptrx);
Console.WriteLine(*ptry + "\t" + (int)ptry);
}
All that had to be done is to change the int*
types to byte* types.
Discussion
A
void pointer has no type and therefore cannot be
dereferenced, nor can pointer arithmetic be applied to this type of
pointer. A void pointer does have one very useful
function, though; it can be cast to a pointer of any other type. A
void pointer is also able to be cast to the
following other value types as well:
sbyte
|
int
|
byte
|
uint
|
short
|
long
|
ushort
|
ulong
|
In the Switch method, used in the Solution for
this recipe, we notice that it takes two parameters by reference of
type void*. We are declaring that any pointer type
may be passed to these two parameters on this method. Once inside the
Switch method, we can manipulate the value
contained in the void pointers. However, since we
do not know the original type that the void* was
cast from, we cannot dereference the void*.
The one drawback to this technique is that before the
Switch method is called in the
TestSwitch method, the int* or
byte* pointers must be cast to a
void*. When the Switch method
returns, the void* pointers must be cast back to
their original types before they may be used. The reason for this
casting is that we are passing the void* pointers
by reference instead of by value.
We could pass the void* pointers by value instead,
and simply switch the values pointed to, rather than the memory
locations pointed to, in the Switch method. This
new SwitchValues method would look something like
this:
public unsafe void SwitchValues(void* x, void* y)
{
void* temp = x;
*x = *y;
*y = *temp;
}
Unfortunately, this code will not compile, since you cannot
dereference a void*. The void*
must be cast to its original type before it can be dereferenced. To
do this, we must also pass along the type information to the
SwitchValues method. This can become very
cumbersome, and it will reduce the genericity of this method as well.
See Also
See section A.4 Pointer conversions in the C#
specification.
|